
In this example, the categorical response variable is steroid use (yes or no).

In the test of homogeneity, the null hypothesis says that the distribution of a categorical response variable is the same in each population. These institutions do not offer athletic scholarships. Division III consists of colleges and universities that treat athletics as an extracurricular activity for students, instead of a source of revenue. The NCAA limits the amount Division II colleges can spend on athletic scholarships. They have much smaller budgets that come solely from the college. Division II schools tend to be the smaller public universities and many private institutions. These schools tend to be large universities with large athletic budgets supplemented by revenue from the games. Division I schools have to sponsor more sports teams. As before, the chi-square test statistic measures the amount that the observed counts in the samples deviate from the expected counts.Ī note on NCAA divisions: The National Collegiate Athletic Association (NCAA) is divided into three divisions and oversees a wide range of collegiate sports. We must determine what we expect to see in each sample if the distributions are identical. As with all chi-square tests, the expected counts reflect the null hypothesis. To test our hypotheses, we select a random sample from each population and gather data on one categorical variable. This test gets its name from the null hypothesis, where we claim that the distribution of the responses are the same (homogeneous) across groups. Note: Homogeneous means the same in structure or composition. The alternative hypothesis says that the distributions differ. In other words, the proportion with a given response is the same in all of the populations, and this is true for all response categories. The null hypothesis states that the distribution of the categorical variable is the same for the populations (or subgroups).

We have learned the details for two chi-square tests, the goodness-of-fit test, and the test of independence. Conduct a chi-square test of homogeneity.
